initial velocty = 0m/s
final velocity = x m/s
accelaration: -9.8m/s2
distance = -15 m
final velocity squared = initial velocity squared + 2(accelaration)(distance)
x^2 = 0^2 + 2(-9.8)(-15)
x=-17.1 m/s
Edit: it's important to choose a direction to be negative and another to be positive. In this case since acceleration is downwards it's -9.8 and since it's going down the distance is -15.
Thanks youre my hero!
I'm sorry, but if you have a test, and you don't know the most basic equations of motion, you're fucked
Well we never did this specifically, all we did so far was like chemistry nomenclature and significant digits, etc.
especially at the end of the year...lol
I do physics chemistry and biology in one semester, its the same course 70minutes a day.
Well it ended up not being on the test and that chapter that had the question we didnt even cover